Fabian Rohlik
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Given $\det(A) = 8$, what is $\det(A^{-1})$?
det($\begin{bmatrix} 2 & 0 & 0 & 0 \\ 5 & 1 & 0 & 0 \\ 8 & 9 & 2 & 0 \\ 3 & 4 & 5 & 2 \end{bmatrix}$)
Find k: det($\begin{bmatrix} k & 2 \\ 3 & 4 \end{bmatrix}$) = 10
det($\begin{bmatrix} -2 & 5 \\ 4 & -3 \end{bmatrix}$)
Using row reduction, if you divide a row by 3 to simplify the matrix, what must you do to the final result to find the original determinant?